为何匹配不全求原因 ('/$(w+)=(.+?) $/i', $d, $matches2)

程序员文章站 2022-05-04 20:36:43

...

$d = ‘$Row=10 $cid=1 $table=channel $sql=select * form abc $Where=[FatherID]=0 $’

preg_match_all('/\$(\w+)=(.+?) \$/i', $d, $matches2);
if($matches2){
$d2 = '';
for($k=0;$k $d2 = $d2 . $matches2[1][$k] . '="' .$matches2[2][$k] .'" ';
}
}

结果只有 Row="10" table="channel" Where="[FatherID]=0"

应该是 Row="10" cid="1" table="channel" $sql="select * form abc" Where="[FatherID]=0" 才对呀错在哪呢？

回复讨论(解决方案)

应该匹配到5个才对呀为啥只有3个呢求大神给个解决方案

$d = '$Row=10 $cid=1 $table=channel $sql=select * form abc $Where=[FatherID]=0 $';preg_match_all('/\$(\w+)=([^$]+)/i', $d, $matches2);print_r($matches2);

Array(    [0] => Array        (            [0] => $Row=10             [1] => $cid=1             [2] => $table=channel             [3] => $sql=select * form abc             [4] => $Where=[FatherID]=0         )    [1] => Array        (            [0] => Row            [1] => cid            [2] => table            [3] => sql            [4] => Where        )    [2] => Array        (            [0] => 10             [1] => 1             [2] => channel             [3] => select * form abc             [4] => [FatherID]=0         ))

你 /\$(\w+)=(.+?) \$/ 这样写不行的原因是
$Row=10 $cid=1 $table=channel $sql=select * form abc $Where=[FatherID]=0 $
看明白了吗？

用这个规则，你还需要 $d = str_replace('$', '$$', $d),

啊这么笨的正则啊。。。郁闷嗯我改进下谢啦

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为何匹配不全 求原因 ('/$(w+)=(.+?) $/i', $d, $matches2)

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