ajax与php传递和接收变量的实现代码

2. $.ajax({
3. url: 'query.php',
4. data: {id:10},
5. datatype: json
6. success: function(results) {
7. if (results.msg == 'success') {
8. for (var i in data) {
9. $('#content').append(
10. 'id = ' + results.data[i].id + ', description = ' + results.data[i].description + ', msrp = ' + results.data[i].msrp
11. );
12. }
13. } else {
14. $('#content').append(results.msg);
15. }
16. }
17. });

复制代码

php代码：

2. if (isset($_GET['id'])) {
3. $sql = "SELECT id, description, msrp FROM tbl WHERE id = '{$_GET['id']}'";
4. $return = array();
5. if ($result = mysql_query($sql)) {
6. if (mysql_num_rows($result)) {
7. $return['msg'] = 'success';
8. while ($row = mysql_fetch_assoc($result)) {
9. $return['data'][] = $row;
10. }
11. } else {
12. $return['msg'] = 'No results found';
13. } else {
14. $return['msg'] = 'Query failed';
15. }
16. header("Content-type: application/json");
17. echo json_encode($result);
18. }

复制代码