LeetCode 193. Valid Phone Numbers
分析
难度 易
来源
题目
given a text file file.txt
that contains list of phone numbers (one per line), write a one liner bash script to print all valid phone numbers.
you may assume that a valid phone number must appear in one of the following two formats: (xxx) xxx-xxxx or xxx-xxx-xxxx. (x means a digit)
you may also assume each line in the text file must not contain leading or trailing white spaces.
example:
assume that file.txt
has the following content:
987-123-4567
123 456 7890
(123) 456-7890
your script should output the following valid phone numbers:
987-123-4567
(123) 456-7890
解答
https://leetcode.com/problems/valid-phone-numbers/discuss/55478/grep-e-solution-with-detailed-explanation-good-for-those-new-to-regex
1 grep -e '\(^[0-9]\{3\}-[0-9]\{3\}-[0-9]\{4\}$\)' -e '\(^([0-9]\{3\})[ ]\{1\}[0-9]\{3\}-\([0-9]\{4\}\)$\)' file.txt
- in bash, we use \ to escape next one trailing character;
- ^ is used to denote the beginning of a line
- $ is used to denote the end of a line
- {m} is used to denote to match exactly m times of the previous occurence/regex
- (...) is used to group pattern/regex together
back to this problem: it requires us to match two patterns, for better readability, i used -e and separate the two patterns into two regexes, the first one matches this case: xxx-xxx-xxxx and the second one matches this case: (xxx) xxx-xxxx
加上-p(使用perl的正则引擎)即可过滤出目标数据
1 grep -p '^(\d{3}-|\(\d{3}\) )\d{3}-\d{4}$' file.txt
注意上方的空格
1 grep '^(\d{3}-|\(\d{3}\)[ ]{1})\d{3}-\d{4}$' file.txt
这里使用[ ]{1}表示一个空格
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