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asp.net(C#)实现功能强大的时间日期处理类完整实例

程序员文章站 2023-12-13 14:00:10
本文实例讲述了asp.net(c#)实现功能强大的时间日期处理类。分享给大家供大家参考,具体如下: using system; using system.dat...

本文实例讲述了asp.net(c#)实现功能强大的时间日期处理类。分享给大家供大家参考,具体如下:

using system;
using system.data;
using system.configuration;
using system.web;
using system.web.security;
using system.web.ui;
using system.web.ui.webcontrols;
using system.web.ui.webcontrols.webparts;
using system.web.ui.htmlcontrols;
namespace mscl
{
  /// <summary>
  /// 时间日期处理类
  /// </summary>
  public class datetimehelper
  {
    #region 返回本年有多少天
    /// <summary>返回本年有多少天</summary>
    /// <param name="iyear">年份</param>
    /// <returns>本年的天数</returns>
    public static int getdaysofyear(int iyear)
    {
      int cnt = 0;
      if (isruyear(iyear))
      {
        //闰年多 1 天 即:2 月为 29 天
        cnt = 366;
      }
      else
      {
        //--非闰年少1天 即:2 月为 28 天
        cnt = 365;
      }
      return cnt;
    }
    #endregion
    #region 返回本年有多少天
    /// <summary>本年有多少天</summary>
    /// <param name="dt">日期</param>
    /// <returns>本天在当年的天数</returns>
    public static int getdaysofyear(datetime idt)
    {
      int n;
      //取得传入参数的年份部分,用来判断是否是闰年
      n = idt.year;
      if (isruyear(n))
      {
        //闰年多 1 天 即:2 月为 29 天
        return 366;
      }
      else
      {
        //--非闰年少1天 即:2 月为 28 天
        return 365;
      }
    }
    #endregion
    #region 返回本月有多少天
    /// <summary>本月有多少天</summary>
    /// <param name="iyear">年</param>
    /// <param name="month">月</param>
    /// <returns>天数</returns>
    public static int getdaysofmonth(int iyear, int month)
    {
      int days = 0;
      switch (month)
      {
        case 1:
          days = 31;
          break;
        case 2:
          if (isruyear(iyear))
          {
            //闰年多 1 天 即:2 月为 29 天
            days = 29;
          }
          else
          {
            //--非闰年少1天 即:2 月为 28 天
            days = 28;
          }
          break;
        case 3:
          days = 31;
          break;
        case 4:
          days = 30;
          break;
        case 5:
          days = 31;
          break;
        case 6:
          days = 30;
          break;
        case 7:
          days = 31;
          break;
        case 8:
          days = 31;
          break;
        case 9:
          days = 30;
          break;
        case 10:
          days = 31;
          break;
        case 11:
          days = 30;
          break;
        case 12:
          days = 31;
          break;
      }
      return days;
    }
    #endregion
    #region 返回本月有多少天
    /// <summary>本月有多少天</summary>
    /// <param name="dt">日期</param>
    /// <returns>天数</returns>
    public static int getdaysofmonth(datetime dt)
    {
      //--------------------------------//
      //--从dt中取得当前的年,月信息 --//
      //--------------------------------//
      int year, month, days = 0;
      year = dt.year;
      month = dt.month;
      //--利用年月信息,得到当前月的天数信息。
      switch (month)
      {
        case 1:
          days = 31;
          break;
        case 2:
          if (isruyear(year))
          {
            //闰年多 1 天 即:2 月为 29 天
            days = 29;
          }
          else
          {
            //--非闰年少1天 即:2 月为 28 天
            days = 28;
          }
          break;
        case 3:
          days = 31;
          break;
        case 4:
          days = 30;
          break;
        case 5:
          days = 31;
          break;
        case 6:
          days = 30;
          break;
        case 7:
          days = 31;
          break;
        case 8:
          days = 31;
          break;
        case 9:
          days = 30;
          break;
        case 10:
          days = 31;
          break;
        case 11:
          days = 30;
          break;
        case 12:
          days = 31;
          break;
      }
      return days;
    }
    #endregion
    #region 返回当前日期的星期名称
    /// <summary>返回当前日期的星期名称</summary>
    /// <param name="dt">日期</param>
    /// <returns>星期名称</returns>
    public static string getweeknameofday(datetime idt)
    {
      string dt, week = "";
      dt = idt.dayofweek.tostring();
      switch (dt)
      {
        case "mondy":
          week = "星期一";
          break;
        case "tuesday":
          week = "星期二";
          break;
        case "wednesday":
          week = "星期三";
          break;
        case "thursday":
          week = "星期四";
          break;
        case "friday":
          week = "星期五";
          break;
        case "saturday":
          week = "星期六";
          break;
        case "sunday":
          week = "星期日";
          break;
      }
      return week;
    }
    #endregion
    #region 返回当前日期的星期编号
    /// <summary>返回当前日期的星期编号</summary>
    /// <param name="dt">日期</param>
    /// <returns>星期数字编号</returns>
    public static string getweeknumberofday(datetime idt)
    {
      string dt, week = "";
      dt = idt.dayofweek.tostring();
      switch (dt)
      {
        case "mondy":
          week = "1";
          break;
        case "tuesday":
          week = "2";
          break;
        case "wednesday":
          week = "3";
          break;
        case "thursday":
          week = "4";
          break;
        case "friday":
          week = "5";
          break;
        case "saturday":
          week = "6";
          break;
        case "sunday":
          week = "7";
          break;
      }
      return week;
    }
    #endregion
    #region 判断当前日期所属的年份是否是闰年,私有函数
    /// <summary>判断当前日期所属的年份是否是闰年,私有函数</summary>
    /// <param name="dt">日期</param>
    /// <returns>是闰年:true ,不是闰年:false</returns>
    private static bool isruyear(datetime idt)
    {
      //形式参数为日期类型
      //例如:2003-12-12
      int n;
      n = idt.year;
      if ((n % 400 == 0) || (n % 4 == 0 && n % 100 != 0))
      {
        return true;
      }
      else
      {
        return false;
      }
    }
    #endregion
    #region 判断当前年份是否是闰年,私有函数
    /// <summary>判断当前年份是否是闰年,私有函数</summary>
    /// <param name="dt">年份</param>
    /// <returns>是闰年:true ,不是闰年:false</returns>
    private static bool isruyear(int iyear)
    {
      //形式参数为年份
      //例如:2003
      int n;
      n = iyear;
      if ((n % 400 == 0) || (n % 4 == 0 && n % 100 != 0))
      {
        return true;
      }
      else
      {
        return false;
      }
    }
    #endregion
    #region 将输入的字符串转化为日期。如果字符串的格式非法,则返回当前日期
    /// <summary>
    /// 将输入的字符串转化为日期。如果字符串的格式非法,则返回当前日期。
    /// </summary>
    /// <param name="strinput">输入字符串</param>
    /// <returns>日期对象</returns>
    public static datetime convertstringtodate(string strinput)
    {
      datetime odatetime;
      try
      {
        odatetime = datetime.parse(strinput);
      }
      catch (exception)
      {
        odatetime = datetime.today;
      }
      return odatetime;
    }
    #endregion
    #region 将日期对象转化为格式字符串
    /// <summary>
    /// 将日期对象转化为格式字符串
    /// </summary>
    /// <param name="odatetime">日期对象</param>
    /// <param name="strformat">
    /// 格式:
    ///    "shortdate"===短日期
    ///    "longdate"==长日期
    ///    其它====自定义格式
    /// </param>
    /// <returns>日期字符串</returns>
    public static string convertdatetostring(datetime odatetime, string strformat)
    {
      string strdate = "";
      try
      {
        switch (strformat.toupper())
        {
          case "shortdate":
            strdate = odatetime.toshortdatestring();
            break;
          case "longdate":
            strdate = odatetime.tolongdatestring();
            break;
          default:
            strdate = odatetime.tostring(strformat);
            break;
        }
      }
      catch (exception)
      {
        strdate = odatetime.toshortdatestring();
      }
      return strdate;
    }
    #endregion
    #region 判断是否为合法日期,必须大于1800年1月1日
    /// <summary>
    /// 判断是否为合法日期,必须大于1800年1月1日
    /// </summary>
    /// <param name="strdate">输入日期字符串</param>
    /// <returns>true/false</returns>
    public static bool isdatetime(string strdate)
    {
      try
      {
        datetime odate = datetime.parse(strdate);
        if (odate.compareto(datetime.parse("1800-1-1")) > 0)
          return true;
        else
          return false;
      }
      catch (exception)
      {
        return false;
      }
    }
    #endregion
    #region 获取两个日期之间的差值 可返回年 月 日 小时 分钟 秒
    /// <summary>
    /// 获取两个日期之间的差值
    /// </summary>
    /// <param name="howtocompare">比较的方式可为:year month day hour minute second</param>
    /// <param name="startdate">开始日期</param>
    /// <param name="enddate">结束日期</param>
    /// <returns>时间差</returns>
    public static double datediff(string howtocompare, datetime startdate, datetime enddate)
    {
      double diff = 0;
      try
      {
        timespan ts = new timespan(enddate.ticks - startdate.ticks);
        switch (howtocompare.tolower())
        {
          case "year":
            diff = convert.todouble(ts.totaldays / 365);
            break;
          case "month":
            diff = convert.todouble((ts.totaldays / 365) * 12);
            break;
          case "day":
            diff = convert.todouble(ts.totaldays);
            break;
          case "hour":
            diff = convert.todouble(ts.totalhours);
            break;
          case "minute":
            diff = convert.todouble(ts.totalminutes);
            break;
          case "second":
            diff = convert.todouble(ts.totalseconds);
            break;
        }
      }
      catch (exception)
      {
        diff = 0;
      }
      return diff;
    }
    #endregion
    #region 计算两个日期之间相差的工作日天数
    /// <summary>
    /// 计算两个日期之间相差的工作日天数
    /// </summary>
    /// <param name="dtstart">开始日期</param>
    /// <param name="dtend">结束日期</param>
    /// <param name="flag">是否除去周六,周日</param>
    /// <returns>int</returns>
    public static int calculateworkingdays(datetime dtstart, datetime dtend, bool flag)
    {
      int count = 0;
      for (datetime dttemp = dtstart; dttemp < dtend; dttemp = dttemp.adddays(1))
      {
        if (flag)
        {
          if (dttemp.dayofweek != dayofweek.saturday && dttemp.dayofweek != dayofweek.sunday)
          {
            count++;
          }
        }
        else
        {
          count++;
        }
      }
      return count;
    }
    #endregion
  }
}

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