Django 中使用流响应处理视频的方法

<video width="320" height="240" controls>
 <source src="/static/video/demo.mp4" type="video/mp4">
 您的浏览器不支持video标签。
</video>

from django.http import streaminghttpresponse

def hello():
  yield 'hello,'
  yield 'there!'

def test(request):
  return streaminghttpresponse(hello)

import re
import os
from wsgiref.util import filewrapper
from django.http import streaminghttpresponse

def file_iterator(file_name, chunk_size=8192, offset=0, length=none):
  with open(file_name, "rb") as f:
    f.seek(offset, os.seek_set)
    remaining = length
    while true:
      bytes_length = chunk_size if remaining is none else min(remaining, chunk_size)
      data = f.read(bytes_length)
      if not data:
        break
      if remaining:
        remaining -= len(data)
      yield data

def stream_video(request, path):
  """将视频文件以流媒体的方式响应"""
  range_header = request.meta.get('http_range', '').strip()
  range_re = re.compile(r'bytes\s*=\s*(\d+)\s*-\s*(\d*)', re.i)
  range_match = range_re.match(range_header)
  size = os.path.getsize(path)
  content_type, encoding = mimetypes.guess_type(path)
  content_type = content_type or 'application/octet-stream'
  if range_match:
    first_byte, last_byte = range_match.groups()
    first_byte = int(first_byte) if first_byte else 0
    last_byte = first_byte + 1024 * 1024 * 8    # 8m 每片,响应体最大体积
    if last_byte >= size:
      last_byte = size - 1
    length = last_byte - first_byte + 1
    resp = streaminghttpresponse(file_iterator(path, offset=first_byte, length=length), status=206, content_type=content_type)
    resp['content-length'] = str(length)
    resp['content-range'] = 'bytes %s-%s/%s' % (first_byte, last_byte, size)
  else:
    # 不是以视频流方式的获取时，以生成器方式返回整个文件，节省内存
    resp = streaminghttpresponse(filewrapper(open(path, 'rb')), content_type=content_type)
    resp['content-length'] = str(size)
  resp['accept-ranges'] = 'bytes'
  return resp