python实现简单flappy bird

本文实例为大家分享了python实现flappy bird的简单代码，供大家参考，具体内容如下

import pygame
from pygame.locals import *
from sys import exit
import random
 
# 屏幕宽度
screenwidth = 288
# 屏幕高度
screenheight = 512
images = {}
# 背景图片地址
background_path = 'back_ground.png'
pipe_path = 'pipe.png'
base_path = 'base.png'
player_path = (
  'bird2_0.png',
  'bird2_1.png',
  'bird2_2.png',
)
# 初始化
pygame.init()
# 创建窗口
screen = pygame.display.set_mode((screenheight, screenheight))
# 设置窗口标题
pygame.display.set_caption("flappy bird")
 
# 加载图片,透明用convert_alpha,不透明用convert
images['background'] = pygame.image.load(background_path).convert()
images['base'] = pygame.image.load(base_path).convert_alpha()
images['bird'] = (
  pygame.image.load(player_path[0]).convert_alpha(),
  pygame.image.load(player_path[1]).convert_alpha(),
  pygame.image.load(player_path[2]).convert_alpha(),
)
images['pipe'] = (
  pygame.transform.rotate(pygame.image.load(pipe_path).convert_alpha(), 180),
  pygame.image.load(pipe_path).convert_alpha()
 
)
basey = screenheight * 0.82
 
# 设置帧率
fps = 30
fpsclock = pygame.time.clock()
 
pipe_width = images['pipe'][0].get_width()
pipe_height = images['pipe'][0].get_height()
player_width = images['bird'][0].get_width()
player_height = images['bird'][0].get_height()
 
 
pipegapsize = 100 # 两个水管之间的距离
x = screenwidth//2
y = screenheight//2
move_x = 0
move_y = 0
 
flap = 0 # 小鸟初始状态
pipevelx = -4 # 管道x方向的速度
playervely = 0 # 小鸟y方向的初速度
playermaxvely = 10 # 小鸟y方向的最大速度
playerminvely = -8 # 小鸟y方向的最小速度
playeraccy = 2 # 小鸟y方向的下降加速度
playerflapacc = -3 # 小鸟y方向的上升加速度
playerflapped = false # 当小鸟飞的时候为真
playery = int((screenheight - player_height)/2)
 
 
# 随机移动柱子
def getrandompipe():
  # 两个水管之间的距离有如下变量
  gapys = [20, 30, 40, 50, 60, 70, 80, 90]
  index = random.randint(0, len(gapys) - 1)
  gapy = gapys[index]
 
  gapy += int(basey * 0.2)
  # 水管x坐标
  pipex = screenwidth + 10
 
  return [
    {'x': pipex, 'y': gapy - pipe_height},  # 上面水管的左上角位置
    {'x': pipex, 'y': gapy + pipegapsize},  # 下面水管的左上角位置
  ]
 
 
 
 
newpipel = getrandompipe()
 
upperpipes = [
  {'x': screenwidth, 'y':newpipel[0]['y']}
]
lowerpipes = [
  {'x': screenwidth, 'y':newpipel[1]['y']}
]
 
while true:
 
  for event in pygame.event.get():
    if event.type == quit:
      exit()
    elif event.type == keydown:
      if event.key == k_left:
        move_x = -3
      elif event.key == k_right:
        move_x = 3
      elif event.key == k_up:
        move_y = -3
      elif event.key == k_down:
        move_y = 3
    elif event.type == keyup:
      move_x = 0
      move_y = 0
 
  x = x + move_x
  y = y + move_y
 
  # 防止冲出边界
  if x > screenwidth:
    x = 0
  elif x < 0:
    x = screenwidth
 
  if y > screenheight:
    y = 0
  elif y < 0:
    y = screenheight
 
  # 贴图在左上角
  screen.blit(images['background'], (0, 0)) # 背景
  # 显示水管
  for upipe, lpipe in zip(upperpipes, lowerpipes):
    screen.blit(images['pipe'][0], (upipe['x'], upipe['y']))
    screen.blit(images['pipe'][1], (lpipe['x'], lpipe['y']))
 
 
 
  # 放小鸟
  screen.blit(images['bird'][flap], (x, y))
  flap = flap + 1
 
  if flap % 3 == 0:
    flap = 0
 
 
  for upipe, lpipe in zip(upperpipes, lowerpipes):
    upipe['x'] += pipevelx
    lpipe['x'] += pipevelx
 
 
  # 当水管移动到某一位置的时候，生成新的水管
 
  if 0 < upperpipes[0]['x'] < 5:
    newpipe = getrandompipe()
    upperpipes.append(newpipe[0])
    lowerpipes.append(newpipe[1])
  
 
  # 如果水管从右往左移动到边缘，则摧毁水管
  if upperpipes[0]['x'] < -pipe_width:
    # 队列头出队
    upperpipes.pop(0)
    lowerpipes.pop(0)
 
 
  # 刷新画面
  pygame.display.update()
  fpsclock.tick(fps)

以上就是本文的全部内容，希望对大家的学习有所帮助，也希望大家多多支持。