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Oracle中检查外键是否有索引的SQL脚本分享

程序员文章站 2023-01-23 10:12:07
复制代码 代码如下: column columns format a30 word_wrapped column tablename format a15 word_...

复制代码 代码如下:

column columns format a30 word_wrapped
column tablename format a15 word_wrapped
column constraint_name format a15 word_wrapped
select table_name,
       constraint_name,
       cname1 || nvl2(cname2, ',' || cname2, null) ||
       nvl2(cname3, ',' || cname3, null) ||
       nvl2(cname4, ',' || cname4, null) ||
       nvl2(cname5, ',' || cname5, null) ||
       nvl2(cname6, ',' || cname6, null) ||
       nvl2(cname7, ',' || cname7, null) ||
       nvl2(cname8, ',' || cname8, null) columns
  from (select b.table_name,
               b.constraint_name,
               max(decode(position, 1, column_name, null)) cname1,
               max(decode(position, 2, column_name, null)) cname2,
               max(decode(position, 3, column_name, null)) cname3,
               max(decode(position, 4, column_name, null)) cname4,
               max(decode(position, 5, column_name, null)) cname5,
               max(decode(position, 6, column_name, null)) cname6,
               max(decode(position, 7, column_name, null)) cname7,
               max(decode(position, 8, column_name, null)) cname8,
               count(*) col_cnt
          from (select substr(table_name, 1, 30) table_name,
                       substr(constraint_name, 1, 30) constraint_name,
                       substr(column_name, 1, 30) column_name,
                       position
                  from user_cons_columns) a,
               user_constraints b
         where a.constraint_name = b.constraint_name
           and b.constraint_type = 'r'
         group by b.table_name, b.constraint_name) cons
 where col_cnt > all
 (select count(*)
          from user_ind_columns i
         where i.table_name = cons.table_name
           and i.column_name in (cname1, cname2, cname3, cname4, cname5,
                cname6, cname7, cname8)
           and i.column_position <= cons.col_cnt
         group by i.index_name)
/

在上面的基础上修改了一下,可以检查所有的用户。
复制代码 代码如下:

set linesize 400;
column owner format a10 word_wrapped
column columns format a30 word_wrapped
column table_name format a15 word_wrapped
column constraint_name format a40 word_wrapped
select owner,
     table_name,
       constraint_name,
       cname1 || nvl2(cname2, ',' || cname2, null) ||
       nvl2(cname3, ',' || cname3, null) ||
       nvl2(cname4, ',' || cname4, null) ||
       nvl2(cname5, ',' || cname5, null) ||
       nvl2(cname6, ',' || cname6, null) ||
       nvl2(cname7, ',' || cname7, null) ||
       nvl2(cname8, ',' || cname8, null) columns
  from (select b.owner,b.table_name,
               b.constraint_name,
               max(decode(position, 1, column_name, null)) cname1,
               max(decode(position, 2, column_name, null)) cname2,
               max(decode(position, 3, column_name, null)) cname3,
               max(decode(position, 4, column_name, null)) cname4,
               max(decode(position, 5, column_name, null)) cname5,
               max(decode(position, 6, column_name, null)) cname6,
               max(decode(position, 7, column_name, null)) cname7,
               max(decode(position, 8, column_name, null)) cname8,
               count(*) col_cnt
          from (select substr(table_name, 1, 30) table_name,
                       substr(constraint_name, 1, 30) constraint_name,
                       substr(column_name, 1, 30) column_name,
                       position
                  from dba_cons_columns where owner not in ('sys','system','sysman','hr','oe','exfsys','dbsnmp','mdsys','olapsys','scott','exfsys','sh','pm','ctxsys')) a,
               dba_constraints b
         where a.constraint_name = b.constraint_name
           and b.constraint_type = 'r'
         group by b.owner,b.table_name, b.constraint_name) cons
 where col_cnt > all
 (select count(*)
          from dba_ind_columns i
         where i.table_name = cons.table_name and i.table_owner=cons.owner
           and i.column_name in (cname1, cname2, cname3, cname4, cname5,
                cname6, cname7, cname8)
           and i.column_position <= cons.col_cnt
         group by i.index_name)
/