Spring mvc项目改造为Spring boot 问题

1. 打包方式

• jar
• war

jar的方式比较简单，是springboot 默认的。

如果打包war, 部署到外部的tomcat, 需要做以下调整：

• 启动类

@SpringBootApplication
public class WebApplication extends SpringBootServletInitializer {

    @Override
    protected SpringApplicationBuilder configure(SpringApplicationBuilder application) {
        return application.sources(WebApplication.class);
    }

    public static void main(String[] args) {
        SpringApplication.run(WebApplication.class, args);

    }

}

• pom.xml

<dependency>
    <groupId>org.springframework.boot</groupId>
    <artifactId>spring-boot-starter-web</artifactId>
    <exclusions>               
        <exclusion>
            <artifactId>spring-boot-starter-tomcat</artifactId>
            <groupId>org.springframework.boot</groupId>
        </exclusion>
    </exclusions>
</dependency>
<dependency>
     <groupId>org.springframework.boot</groupId>
     <artifactId>spring-boot-starter-tomcat</artifactId>
     <scope>provided</scope>
</dependency>

<build>
    <finalName>appName</finalName>
    <plugins>
        <plugin>
            <groupId>org.springframework.boot</groupId>
            <artifactId>spring-boot-maven-plugin</artifactId>
            <configuration>
                <mainClass>com.***.WebApplication</mainClass>
            </configuration>
            <executions>
                <execution>
                    <goals>
                        <goal>repackage</goal>
                    </goals>
                </execution>
            </executions>
        </plugin>
        <plugin>
            <groupId>org.apache.maven.plugins</groupId>
            <artifactId>maven-war-plugin</artifactId>
            <version>3.3.0</version>
            <configuration>
                <failOnMissingWebXml>false</failOnMissingWebXml>
            </configuration>
        </plugin>
   </plugins>
       
</build>

• 去掉原web.xml

如果原来mvc项目包含web.xml文件，需要去掉，否则tomcat启动时日志会打印：启动一个或多个listener异常，导致tomcat启动失败，访问会报404。

因springboot 已经对web.xml 功能做了启动封装，无需web.xml文件，否则会有冲突。

参考：https://uhfun.cn/tech/2020/05/22/%E4%B8%BA%E4%BB%80%E4%B9%88SpringBoot%E9%A1%B9%E7%9B%AE%E4%B8%8D%E9%9C%80%E8%A6%81web.xml.html

2. Spring Boot设置访问url接口后缀

传统的xml配置方式

<servlet>
    <servlet-name>dispatcherServlet</servlet-name>
    <servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
    <init-param>
        <param-name>contextConfigLocation</param-name>
        <param-value>classpath:conf/spring-mvc.xml</param-value>
    </init-param>
    <load-on-startup>1</load-on-startup>
</servlet>
 
<servlet-mapping>
    <servlet-name>dispatcherServlet</servlet-name>
    <url-pattern>*.do</url-pattern>
</servlet-mapping>

Spring Boot配置方式

application.yml

spring:
  mvc:
    contentnegotiation:
      favor-path-extension: true
    pathmatch:
      use-suffix-pattern: true
      use-registered-suffix-pattern: true

启动加载配置类

@Configuration
public class WebMvcConfig implements WebMvcConfigurer {

    /**
     * -设置url后缀模式匹配规则
     * -该设置匹配所有的后缀，使用.do或.action都可以
     */
    @Override
    public void configurePathMatch(PathMatchConfigurer configurer) {
        configurer.setUseSuffixPatternMatch(true) //设置是否是后缀模式匹配,即:/test.*
                .setUseTrailingSlashMatch(true) //设置是否自动后缀路径模式匹配,即：/test/
                .setUseRegisteredSuffixPatternMatch(false); //开启路径后缀匹配
    }

    /**
     * -该设置严格指定匹配后缀*.do或.action，但有风险
     * @param dispatcherServlet servlet调度器
     * @return ServletRegistrationBean
     */
//    @Bean
    public ServletRegistrationBean servletRegistrationBean(DispatcherServlet dispatcherServlet) {
    	ServletRegistrationBean<DispatcherServlet> servletServletRegistrationBean = new ServletRegistrationBean<>(dispatcherServlet);
        servletServletRegistrationBean.addUrlMappings("*.do");//指定.do后缀，可替换其他后缀
        return servletServletRegistrationBean;
    }

配置类使用上面第一种方式即可，第二种本人试了有问题，无法正常访问。

 

本文地址：https://blog.csdn.net/qq_27641935/article/details/109578207