已知十个经纬度点怎么来判断其中一个经纬度点（确定）距离最近的经纬度点 已知十个经纬度点怎么来判断一个经纬度点（确定）距离这十个经纬度点最近的经纬度点 或者判断其中一个经纬度点（确定）距离这十个经纬度点

private static final  double EARTH_RADIUS = 6378137;//赤道半径(单位m)
/** 
 * 转化为弧度(rad) 
 * */  
private static double rad(double d)  
{  
   return d * Math.PI / 180.0;  
} 

/** 
 * 基于余弦定理求两经纬度距离 
 * @param lon1 第一点的精度 
 * @param lat1 第一点的纬度 
 * @param lon2 第二点的精度 
 * @param lat3 第二点的纬度 
 * @return 返回的距离，单位km 
 * */  
public static double LantitudeLongitudeDist(double lon1, double lat1,double lon2, double lat2) {  
    double radLat1 = rad(lat1);  
    double radLat2 = rad(lat2);  

    double radLon1 = rad(lon1);  
    double radLon2 = rad(lon2);  

    if (radLat1 < 0)  
        radLat1 = Math.PI / 2 + Math.abs(radLat1);// south  
    if (radLat1 > 0)  
        radLat1 = Math.PI / 2 - Math.abs(radLat1);// north  
    if (radLon1 < 0)  
        radLon1 = Math.PI * 2 - Math.abs(radLon1);// west  
    if (radLat2 < 0)  
        radLat2 = Math.PI / 2 + Math.abs(radLat2);// south  
    if (radLat2 > 0)  
        radLat2 = Math.PI / 2 - Math.abs(radLat2);// north  
    if (radLon2 < 0)  
        radLon2 = Math.PI * 2 - Math.abs(radLon2);// west  
    double x1 = EARTH_RADIUS * Math.cos(radLon1) * Math.sin(radLat1);  
    double y1 = EARTH_RADIUS * Math.sin(radLon1) * Math.sin(radLat1);  
    double z1 = EARTH_RADIUS * Math.cos(radLat1);  

    double x2 = EARTH_RADIUS * Math.cos(radLon2) * Math.sin(radLat2);  
    double y2 = EARTH_RADIUS * Math.sin(radLon2) * Math.sin(radLat2);  
    double z2 = EARTH_RADIUS * Math.cos(radLat2);  

    double d = Math.sqrt((x1 - x2) * (x1 - x2) + (y1 - y2) * (y1 - y2)+ (z1 - z2) * (z1 - z2));  
    //余弦定理求夹角  
    double theta = Math.acos((EARTH_RADIUS * EARTH_RADIUS + EARTH_RADIUS * EARTH_RADIUS - d * d) / (2 * EARTH_RADIUS * EARTH_RADIUS));  
    double dist = theta * EARTH_RADIUS;  
    return dist;  
}