python实现AES加解密文档里英文字符串**

python实现AES加解密文档里英文文章**

AES加解密文档里英文字符串
英文文档中也包含了空格与回车符

加密过程

首先读取文件中的内容

将文档中的内容读取，然后将其赋予你申请的变量 在我的实验中我的申请的变量的名字是message

outputFilename = input('what is name to encrypted file:',)#'I believe I can fly_1.txt'
        fileobj = open(inputfilename,encoding='utf-8')
        message = fileobj.read()
        fileobj.close()

读取出来后回车符都变成\n

将读出的字符串转成16进制字符串

首先将读出的message放到一个列表list1中
然后将列表里面的字符串按照字符的顺序循环读出元素并转化成16进制字符串，同时将这个字符串写入一个新列表list2
由于我的方式中回车符是一个16进制字符代表，我的代码中表示是a 因为这个会导致后面的加解密更复杂，所以利用0a代替a 最后导入一个新列表
申请一个变量，将列表中的元素读出，赋值给这个变量名，并且将每个16进制的元素前面的0x删去，再赋值给另外一个变量

list1 = list(message)
list2 = []
for i in list1:
    i_by = i.encode('utf-8')
    for i_bin in i_by:
        list2.append(hex(i_bin))
list3 = ['0x0a' if j == '0xa' else j for j in list2]
print(len(list3))
 b = ''.join(list3)
m = re.sub('0x', '', b)
M = m

因为AES代码是基于一个博主的代码（链接在本文文底），代码只能加密32个16进制的字符

切割字符

将字符串切割，每32个字符作为一组，然后加进一个新的列表中

        h1 = len(M) // 32#计算整除
        h2 = len(M) % 32#计算是否为0，若为0则切割轮数就是h1，若不为0则是h1+1
        list4 = []
        for step in range(0, h1 + 1):
            h3 = M[step * 32:32 * (step + 1)]
            list4.append(h2)
        list5 = list4

进行加密

 for number in list5:
        h4 = '0x'+number
        k=key
        RoundKeys = aes.round_key_generator(k)

        plaintext = eval(h4)
        plaintext = aes.num_2_16bytes(plaintext)
        print(plaintext)
        ciphertext = aes.aes_encrypt(plaintext, RoundKeys)
        list6.append(hex(aes._16bytes2num(ciphertext)))
        print('ciphertext = ' + hex(aes._16bytes2num(ciphertext)))

进行加密后的密文处理

因为切割后如果进行加密的列表中有的元素中可能第一个字符是0，使用该加密算法后会自动吞掉，所以我们要对密文进行处理后再写入一个新文档（如果需要解密的话进行此步骤，不用解密不影响）

        for i1 in range(0,len(list6)):
            list6[i1]=re.sub('0x','',list6[i1])
            if len(list6[i1])<32:
                list6[i1]='0'*(32-len(list6[i1]))+list6[i1]
            print(i1)a
            print(list6[i1])
        a = ''.join(list6)
        a =re.sub('0x','',a)
        fo = open(outputFilename, 'w')
        fo.write(a)
        fo.close()

至此加密过程结束
PS：文档中是中文也可以用此方法加密

解密过程

读取你想加密的文件

 outputFilename = input('what is name to decrypted file:' )  # 'I believe I can fly_2.txt'
      fileobj = open(inputfilename)
      message = fileobj.read()
      fileobj.close()

切割字符串

 list1=[]
      h1 = len(message) // 32#计算整除
      h3 = len(message) % 32#计算是否为0，若为0则切割轮数就是h1，若不为0则是h1+1
      print(h1)
      print(h3)
      for step in range(0, h1):
          h2 = message[step * 32:32 * (step + 1)]
          list1.append(h2)

进行解密

 list2 = []
      for number in list1:
          h4 ='0x'+number
          k = key#0x0f1571c947d9e8590cb7add6af7f6798
          RoundKeys = aes.round_key_generator(k)
          ciphertext = eval(h4)
          ciphertext = aes.num_2_16bytes(ciphertext)
          ciphertext = aes.aes_decrypt(ciphertext, RoundKeys)
          list2.append(hex(aes._16bytes2num(ciphertext)))

进行解密后的密文处理

因为切割后如果进行解密的列表中有的元素中可能第一个字符是0，使用该解密算法后会自动吞掉，所以我们要对明文进行处理后再写入一个新文档

      for i1 in range(0, len(list2)):
          list2[i1] = re.sub('0x', '', list2[i1])
          if len(list2[i1]) < 32:
              list2[i1] = '0' * (32 - len(list2[i1])) + list2[i1]
          print(i1)
          print(list2[i1])
      b = ''.join(list2)
      b = re.sub('0x', '', b)
      fo = open(outputFilename, 'w')
      fo.write(b)
      fo.close()

将16进制转化为英文字符

16进制转字符我借鉴了一个函数

def decode(s):
    return ''.join([chr(i) for i in [int(b, 2) for b in s.split(' ')]])

转化的过程

首先将16进制的明文读出 然后将其每两位为一组进行切割并且在每组前面加上16进制特有的0x，同时将每组按照顺序写入一个新列表
再将0x0a改回0xa 最后将获得的明文内容赋值于申请的变量，然后将其写入一个新文档

fileobj_1=open(outputFilename)
      message_1=fileobj_1.read()
      fileobj_1.close()
      h5=len(message_1)//2#计算整除
      h6=len(message_1)%2#计算是否为0，若为0则切割轮数就是h5，若不为0则是h5+1
      print(h5)
      list3=[]
      for step in range(0, h5):
          h2 = '0x'+message_1[step * 2:2 * (step + 1)]
          list3.append(h2)
      list4 = ['0xa' if i == '0x0a' else i for i in list3]
      print(list4)
      list5=[]
      list6=[]
      for j in list4:
          list5.append(bin(int(j, 16)).replace('0b', ''))
      print(list5)
      for h in list5:
        k = decode(h)
        list6.append(k)
      a = ''.join(list6)
      print(a)
      outputFilename_1=input('what is name to decrypted file:')
      fo_1 = open(outputFilename_1, 'w')
      fo_1.write(a)
      fo_1.close()

至此解密结束
PS：此解密方法只能适用于英文(中文可以解密，转换时出现问题)，中文由于本人学艺不精，不会将中文转码，转出是乱码。

放上实现每一步的图：

1.将文字转化为16进制

2.文件加密

3.解密

4.将解密的结果转化为字符

最后放入完整的我写的主函数的代码

 aes = AES()
    key = input('input your key:')
    key=eval(key)

    mode = input('please input encrypt or decrypt:')
#加密
    if mode=='encrypt':
        inputfilename=input('print you want encrypt filename:')#'I believe I can fly .txt'
        if not os.path.exists(inputfilename):
            print('the file %s does not exist.Quitting' % (inputfilename))
            sys.exit()
        outputFilename = input('what is name to encrypted file:',)#'I believe I can fly_1.txt'
        fileobj = open(inputfilename,encoding='utf-8')
        message = fileobj.read()
        fileobj.close()
        list1 = list(message)
        list2 = []
        for i in list1:
            i_by = i.encode('utf-8')
            for i_bin in i_by:
                list2.append(hex(i_bin))
        list3 = ['0x0a' if j == '0xa' else j for j in list2]
        print(len(list3))
        b = ''.join(list3)
        m = re.sub('0x', '', b)
        print(m)
        M = m
        h1 = len(M) // 32
        h3 = len(M) % 32
        print(h1)
        print(h3)
        list4 = []
        for step in range(0, h1 + 1):
            h2 = M[step * 32:32 * (step + 1)]
            list4.append(h2)
        list5 = list4
        print(list5)
        list6 = []
        for number in list5:
            h4 = '0x'+number
            k=key
            RoundKeys = aes.round_key_generator(k)

            plaintext = eval(h4)
            plaintext = aes.num_2_16bytes(plaintext)
            print(plaintext)
            ciphertext = aes.aes_encrypt(plaintext, RoundKeys)
            list6.append(hex(aes._16bytes2num(ciphertext)))
            print('ciphertext = ' + hex(aes._16bytes2num(ciphertext)))
             #print()0x0f1571c947d9e8590cb7add6af7f6798
        for i1 in range(0,len(list6)):
            list6[i1]=re.sub('0x','',list6[i1])
            if len(list6[i1])<32:
                list6[i1]='0'*(32-len(list6[i1]))+list6[i1]
            print(i1)
            print(list6[i1])
        b = ''.join(list6)
        b =re.sub('0x','',b)
        fo = open(outputFilename, 'w')
        fo.write(b)
        fo.close()
        #解密
    elif mode == 'decrypt':
      inputfilename = input('print you want decrypt filename:')  # 'I believe I can fly_1.txt'
      if not os.path.exists(inputfilename):
            print('the file %s does not exist.Quitting' % (inputfilename))
            sys.exit()
      outputFilename = input('what is name to decrypted file:' )  
      fileobj = open(inputfilename)
      message = fileobj.read()
      fileobj.close()
      list1=[]
      h1 = len(message) // 32
      h3 = len(message) % 32
      print(h1)
      print(h3)
      for step in range(0, h1):
          h2 = message[step * 32:32 * (step + 1)]
          list1.append(h2)
      list2 = []
      for number in list1:
          h4 ='0x'+number
          k = key
          RoundKeys = aes.round_key_generator(k)
          ciphertext = eval(h4)
          ciphertext = aes.num_2_16bytes(ciphertext)
          ciphertext = aes.aes_decrypt(ciphertext, RoundKeys)
          list2.append(hex(aes._16bytes2num(ciphertext)))
      for i1 in range(0, len(list2)):
          list2[i1] = re.sub('0x', '', list2[i1])
          if len(list2[i1]) < 32:
              list2[i1] = '0' * (32 - len(list2[i1])) + list2[i1]
          print(i1)
          print(list2[i1])
      b = ''.join(list2)
      b = re.sub('0x', '', b)
      fo = open(outputFilename, 'w')
      fo.write(b)
      fo.close()
      fileobj_1=open(outputFilename)
      message_1=fileobj_1.read()
      fileobj_1.close()
      h5=len(message_1)//2
      h6=len(message_1)%2
      print(h5)
      list3=[]
      for step in range(0, h5):
          h2 = '0x'+message_1[step * 2:2 * (step + 1)]
          list3.append(h2)
      list4 = ['0xa' if i == '0x0a' else i for i in list3]
      print(list4)
      list5=[]
      list6=[]
      for j in list4:
          list5.append(bin(int(j, 16)).replace('0b', ''))
      print(list5)
      for h in list5:
        k = decode(h)
        list6.append(k)
      a = ''.join(list6)
      print(a)
      outputFilename_1=input('what is name to decrypted file:')
      fo_1 = open(outputFilename_1, 'w')
      fo_1.write(a)
      fo_1.close()
    else:
      print('wrong input！')

PS：使用主函数时别忘记上面的一个转字符的代码哦

加密的文档

I believe I can fly


I used to think that I could not go on
And life was nothing but an awful song
But now I know the meaning of true love
I'm leaning on the everlasting arms
If I can see it, then I can do it
If I just believe it, there's nothing to it
I believe I can fly
I believe I can touch the sky
I think about it every night and day (Night and day)
Spread my wings and fly away
I believe I can soar
I see me running through that open door
I believe I can fly
I believe I can fly
I believe I can fly hoo
meaning byGirlgirl3ooo
I think they mean that it can help your with the song See All
See I was on the verge of breaking down
Sometimes silence can seem so loud
There are miracles in life I must achieve
But first I know it starts inside of me, ho oh
If I can see it hoo, then I can be it
If I just believe it, there's nothing to it
I believe I can fly
I believe I can touch the sky
I think about it every night and day
Spread my wings and fly away
I believe I can soar
I see me running through that open door
I believe I can fly
I believe I can fly
Oh, I believe I can fly hoo
Hey, 'cause I believe in me, oh
If I can see it hoo, then I can do it
If I just believe it, there's nothing to it hey
I believe I can fly hoo
I believe I can touch the sky
I think about it every night and day
Spread my wings and fly away
I believe I can soar
I see me running through that open door
I believe I can fly (I can fly)
I believe I can fly (I can fly)
I believe I can fly (I can fly) hey
If I just spread my wings (I can fly)
I can fly (I can fly)
I can fly (I can fly)
I can fly,(I can fly) hey
If I just spread my wings (I can fly)
I can fly (I can fly)
(I can fly)
(I can fly)

注意

本文章的代码是基于借鉴的AES代码，所以具有在加解密时候的局限性，需要按照32个字符为一组将明文切割加密和密文切割解密，如果是其他的字符个数可以自行改动参数。

最后

本人还是一个新手，在本代码中的变量命名有点简单，可能代码有的复杂，希望大佬们不要介意。而且可能中间有的地方写的不够好，希望大佬指正，还有最后中文转码，如果有大佬了解的希望可以教我一下，谢谢。

AES代码借鉴于（加解密都有哦）：https://blog.csdn.net/weixin_42580862/article/details/101703941

本文地址：https://blog.csdn.net/qq_44847088/article/details/111143659