PHP中遇到AJAX的有关问题

程序员文章站 2022-06-15 19:46:27

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PHP中遇到AJAX的问题

header("Content-Type:html/text;Charset=utf-8");
$name = $_POST['name'];
$email = $_POST['email'];
$comment = $_POST['comment'];
$fh = @fopen("14-6.txt","ab");
fwrite($fh,"姓名:".$name,strlen($name));
fwrite($fh,"email:".$email,strlen($email));
fwrite($fh,"评论:".$comment,strlen($comment));
fclose($fh);
echo 1;
?>

function $(id){
	return document.getElementById(id);
}
function addcomment(){
	var url = "14-6.php";
	var status = document.getElementById("divmsg");
	status.value="正在提交》》》";
	var param = "name="+$("name").value+"email="+$("email").value+"comment="+$("comment").value;
	xmlhttp_request.onreadystatechange = function(){
		if(xmlhttp_request.readyState==4 && xmlhttp_request.status == 200){//相应完全显示信息
			alert (xmlhttp_request.responseText);
			if(xmlhttp_request.responseText == "1"){
				status.value = "发表成功！！";
				$("name").value="";
				$("email").value="";
				$("comment").value="";
			}else{
				status.value = "发表失败！请重新发表！";
			}
		}	
	}
	xmlhttp_request.open("POST",url,true);
	xmlhttp_request.setRequestHeader("Content-Type","application/x-www-form-urlencoded");//设置头信息
	xmlhttp_request.send(param);
}