CREATE TABLE student (
id INT(10)not null unique primary key,
name VARCHAR(20) NOT NULL,
sex VARCHAR(4),
birth YEAR,
department VARCHAR(20),
address VARCHAR(50)
);
创建score表。SQL代码如下:
CREATE TABLE score (
id INT(10) NOT NULL UNIQUE PRIMARY KEY AUTO_INCREMENT,
stu_id INT(10) NOT NULL,
c_name VARCHAR(20),
grade INT(10)
);
向student表插入记录的INSERT语句如下:
INSERT INTO student VALUES( 901,'张老大', '男',1985,'计算机系', '北京市海淀区');
INSERT INTO student VALUES( 902,'张老二', '男',1986,'中文系', '北京市昌平区');
INSERT INTO student VALUES( 903,'张三', '女',1990,'中文系', '湖南省永州市');
INSERT INTO student VALUES( 904,'李四', '男',1990,'英语系', '辽宁省阜新市');
INSERT INTO student VALUES( 905,'王五', '女',1991,'英语系', '福建省厦门市');
INSERT INTO student VALUES( 906,'王六', '男',1988,'计算机系', '湖南省衡阳市');
向score表插入记录的INSERT语句如下:
INSERT INTO score VALUES(NULL,901, '计算机',98);
INSERT INTO score VALUES(NULL,901, '英语', 80);
INSERT INTO score VALUES(NULL,902, '计算机',65);
INSERT INTO score VALUES(NULL,902, '中文',88);
INSERT INTO score VALUES(NULL,903, '中文',95);
INSERT INTO score VALUES(NULL,904, '计算机',70);
INSERT INTO score VALUES(NULL,904, '英语',92);
INSERT INTO score VALUES(NULL,905, '英语',94);
INSERT INTO score VALUES(NULL,906, '计算机',90);
INSERT INTO score VALUES(NULL,906, '英语',85);
SELECT * FROM student;
SELECT * FROM student WHERE id>=902 AND id <=904;
SELECT id,name,department FROM student;
SELECT * FROM student WHERE department='计算机系' OR department='英语系';
SELECT * FROM student WHERE birth>=1998 AND birth <=2002;
SELECT department,count(*) FROM student GROUP BY department;
SELECT c_name,max(grade) FROM score GROUP BY c_name;
SELECT s.name as name,sc.c_name as c_name,sc.grade as grade FROM student as s join score as sc ON(s.id = sc.stu_id) WHERE name ='李四';
SELECT * from student as s JOIN score as sc on(s.id=sc.stu_id);
SELECT student.id as id,name,SUM(grade) FROM student,score WHERE student.id=score.stu_id GROUP BY id;
SELECT c_name,AVG(grade) FROM score GROUP BY c_name;
SELECT * FROM student WHERE id IN(SELECT stu_id FROM score WHERE c_name="计算机" and grade<95);
SELECT * FROM student WHERE id =ANY(SELECT stu_id FROM score WHERE stu_id IN ( SELECT stu_id FROM score WHERE c_name='计算机') AND c_name='英语' );
SELECT stu_id, grade FROM score WHERE c_name= '计算机' ORDER BY grade DESC;
SELECT id FROM student UNION SELECT stu_id FROM score;
SELECT student.id, name,sex,birth,department, address, c_name,grade FROM student, score WHERE(name LIKE '张%' OR name LIKE '王%')AND student.id=score.stu_id ;
SELECT student.id, name,sex,birth,department, address, c_name,grade FROM student, score WHERE address LIKE '湖南%' AND student.id=score.stu_id;
本文地址:https://blog.csdn.net/qq_44923097/article/details/108987059